10x^2+8x-10=6x

Solution for 10x^2+8x-10=6x equation:

10x^2+8x-10=6x

We move all terms to the left:

10x^2+8x-10-(6x)=0

We add all the numbers together, and all the variables

10x^2+2x-10=0

a = 10; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·10·(-10)
Δ = 404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{404}=\sqrt{4*101}=\sqrt{4}*\sqrt{101}=2\sqrt{101}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{101}}{2*10}=\frac{-2-2\sqrt{101}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{101}}{2*10}=\frac{-2+2\sqrt{101}}{20}
$